Optimal. Leaf size=199 \[ -\frac{2 \sqrt{\cos (a+b x)}}{b \sqrt{\sin (a+b x)}}+\frac{\tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}\right )}{\sqrt{2} b}-\frac{\tan ^{-1}\left (\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}+1\right )}{\sqrt{2} b}-\frac{\log \left (\tan (a+b x)-\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}+1\right )}{2 \sqrt{2} b}+\frac{\log \left (\tan (a+b x)+\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}+1\right )}{2 \sqrt{2} b} \]
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Rubi [A] time = 0.11384, antiderivative size = 199, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 8, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.381, Rules used = {2567, 2574, 297, 1162, 617, 204, 1165, 628} \[ -\frac{2 \sqrt{\cos (a+b x)}}{b \sqrt{\sin (a+b x)}}+\frac{\tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}\right )}{\sqrt{2} b}-\frac{\tan ^{-1}\left (\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}+1\right )}{\sqrt{2} b}-\frac{\log \left (\tan (a+b x)-\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}+1\right )}{2 \sqrt{2} b}+\frac{\log \left (\tan (a+b x)+\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}+1\right )}{2 \sqrt{2} b} \]
Antiderivative was successfully verified.
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Rule 2567
Rule 2574
Rule 297
Rule 1162
Rule 617
Rule 204
Rule 1165
Rule 628
Rubi steps
\begin{align*} \int \frac{\cos ^{\frac{3}{2}}(a+b x)}{\sin ^{\frac{3}{2}}(a+b x)} \, dx &=-\frac{2 \sqrt{\cos (a+b x)}}{b \sqrt{\sin (a+b x)}}-\int \frac{\sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}} \, dx\\ &=-\frac{2 \sqrt{\cos (a+b x)}}{b \sqrt{\sin (a+b x)}}-\frac{2 \operatorname{Subst}\left (\int \frac{x^2}{1+x^4} \, dx,x,\frac{\sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}\right )}{b}\\ &=-\frac{2 \sqrt{\cos (a+b x)}}{b \sqrt{\sin (a+b x)}}+\frac{\operatorname{Subst}\left (\int \frac{1-x^2}{1+x^4} \, dx,x,\frac{\sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}\right )}{b}-\frac{\operatorname{Subst}\left (\int \frac{1+x^2}{1+x^4} \, dx,x,\frac{\sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}\right )}{b}\\ &=-\frac{2 \sqrt{\cos (a+b x)}}{b \sqrt{\sin (a+b x)}}-\frac{\operatorname{Subst}\left (\int \frac{1}{1-\sqrt{2} x+x^2} \, dx,x,\frac{\sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}\right )}{2 b}-\frac{\operatorname{Subst}\left (\int \frac{1}{1+\sqrt{2} x+x^2} \, dx,x,\frac{\sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}\right )}{2 b}-\frac{\operatorname{Subst}\left (\int \frac{\sqrt{2}+2 x}{-1-\sqrt{2} x-x^2} \, dx,x,\frac{\sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}\right )}{2 \sqrt{2} b}-\frac{\operatorname{Subst}\left (\int \frac{\sqrt{2}-2 x}{-1+\sqrt{2} x-x^2} \, dx,x,\frac{\sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}\right )}{2 \sqrt{2} b}\\ &=-\frac{\log \left (1-\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}+\tan (a+b x)\right )}{2 \sqrt{2} b}+\frac{\log \left (1+\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}+\tan (a+b x)\right )}{2 \sqrt{2} b}-\frac{2 \sqrt{\cos (a+b x)}}{b \sqrt{\sin (a+b x)}}-\frac{\operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}\right )}{\sqrt{2} b}+\frac{\operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}\right )}{\sqrt{2} b}\\ &=\frac{\tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}\right )}{\sqrt{2} b}-\frac{\tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}\right )}{\sqrt{2} b}-\frac{\log \left (1-\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}+\tan (a+b x)\right )}{2 \sqrt{2} b}+\frac{\log \left (1+\frac{\sqrt{2} \sqrt{\sin (a+b x)}}{\sqrt{\cos (a+b x)}}+\tan (a+b x)\right )}{2 \sqrt{2} b}-\frac{2 \sqrt{\cos (a+b x)}}{b \sqrt{\sin (a+b x)}}\\ \end{align*}
Mathematica [C] time = 0.0352818, size = 55, normalized size = 0.28 \[ -\frac{2 \cos ^2(a+b x)^{3/4} \, _2F_1\left (-\frac{1}{4},-\frac{1}{4};\frac{3}{4};\sin ^2(a+b x)\right )}{b \sqrt{\sin (a+b x)} \cos ^{\frac{3}{2}}(a+b x)} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.079, size = 953, normalized size = 4.8 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cos \left (b x + a\right )^{\frac{3}{2}}}{\sin \left (b x + a\right )^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cos ^{\frac{3}{2}}{\left (a + b x \right )}}{\sin ^{\frac{3}{2}}{\left (a + b x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cos \left (b x + a\right )^{\frac{3}{2}}}{\sin \left (b x + a\right )^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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